feat(naive): don't repeat the same char on the same index, unless it is matched #2

src/solve/naive/mod.rs

@@ -1,10 +1,8 @@
-use core::panic;
 use std::collections::HashMap;
 
 use libpt::log::{debug, info, trace};
 
 use crate::error::{SolverError, WResult};
-use crate::game::response;
 use crate::wlist::word::{Word, WordData};
 use crate::wlist::WordList;
 
@@ -31,7 +29,8 @@ impl<'wl, WL: WordList> Solver<'wl, WL> for NaiveSolver<'wl, WL> {
     ///   word, but don't know the position of.
     fn guess_for(&self, game: &crate::game::Game<WL>) -> WResult<Word> {
         let mut pattern: String = ".".repeat(game.length());
-        let mut other_chars: Vec<char> = Vec::new();
+        // char and then the indexes we tried for that already
+        let mut other_chars: HashMap<char, Vec<usize>> = HashMap::new();
         // a hash map telling how many of the characters may be in a correct word (+1)
         // if the value for a char is 2 => it may be in the solution 1 time
         // if the value for a char is 1 => it may not be in the solution
@@ -43,13 +42,19 @@ impl<'wl, WL: WordList> Solver<'wl, WL> for NaiveSolver<'wl, WL> {
                     Status::Matched => {
                         pattern.replace_range(idx..idx + 1, &p.0.to_string());
                     }
-                    Status::Exists => other_chars.push(p.0),
+                    Status::Exists => {
+                        other_chars.entry(p.0).or_default();
+                        let v = other_chars.get_mut(&p.0).unwrap();
+                        v.push(idx);
+                    }
                     Status::None => wrong_chars.push(p.0),
                 }
             }
         }
         debug!("other chars: {:?}", other_chars);
         debug!("wrong chars: {:?}", wrong_chars);
+
+        // get all words that have the correct chars on the same positions
         let mut matches: Vec<WordData> = game.wordlist().get_words_matching(&pattern)?;
         if matches.is_empty() {
             return Err(SolverError::NoMatches(game.solution().cloned()).into());
@@ -60,10 +65,21 @@ impl<'wl, WL: WordList> Solver<'wl, WL> for NaiveSolver<'wl, WL> {
             .filter(|p| !game.made_guesses().contains(&&p.0))
             // only words that do contain the chars we know exist
             .filter(|p| {
-                for other in &other_chars {
+                for other in other_chars.iter() {
-                    if p.0.contains(*other) {
+                    if p.0.contains(*other.0) {
-                        // TODO: account for chars that occur multiple times
+                        let mut already_tried: Vec<(_, _)> = Vec::new();
-                        continue;
+                        for spot in other.1 {
+                            already_tried.push((*spot, *other.0));
+                        }
+
+                        if p.0
+                            .char_indices()
+                            .filter(|ci| ci.1 == *other.0 && !already_tried.contains(ci))
+                            .count()
+                            < 1
+                        {
+                            return false;
+                        }
                     } else {
                         return false;
                     }
@@ -73,13 +89,13 @@ impl<'wl, WL: WordList> Solver<'wl, WL> for NaiveSolver<'wl, WL> {
             // only words that do not contain the letters we know are wrong
             .filter(|p| {
                 for wrong in &wrong_chars {
+                    let in_other = other_chars.iter().filter(|v| *v.0 == *wrong).count()
+                        + pattern.chars().filter(|v| *v == *wrong).count();
                     if p.0.contains(*wrong) {
-                        let mut tmp = 0;
+                        // HACK: something is still not quite right here, we basically ignore all
-                        let in_other = other_chars.iter().filter(|v| **v == *wrong).count()
+                        // wrong chars if they occur in other_chars at least once, which can't be
-                            + pattern.chars().filter(|v| *v == *wrong).count();
+                        // fully correct.
-                        // TODO: account for chars that occur multiple times
+                        if in_other > 0 {
-                        if in_other > tmp {
-                            tmp += 1;
                             continue;
                         }
                         return false;