hacky but fixed modular exponentiation
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937622134b
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26fe9ed776
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@ -19,6 +19,10 @@ struct Cli {
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/// Machine output
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/// Machine output
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#[arg(short, long, default_value_t = false, global = true)]
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#[arg(short, long, default_value_t = false, global = true)]
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machine: bool,
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machine: bool,
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/// Verbose output
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#[arg(short, long, default_value_t = false, global = true)]
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verbose: bool,
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}
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}
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#[derive(Subcommand, Debug)]
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#[derive(Subcommand, Debug)]
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@ -79,7 +83,7 @@ pub fn main() {
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let b = num_bigint::BigInt::from_str(&mod_exp_args.base.as_str()).expect("could not make bigint");
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let b = num_bigint::BigInt::from_str(&mod_exp_args.base.as_str()).expect("could not make bigint");
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let e = num_bigint::BigInt::from_str(&mod_exp_args.exp.as_str()).expect("could not make bigint");
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let e = num_bigint::BigInt::from_str(&mod_exp_args.exp.as_str()).expect("could not make bigint");
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let f = num_bigint::BigInt::from_str(&mod_exp_args.field.as_str()).expect("could not make bigint");
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let f = num_bigint::BigInt::from_str(&mod_exp_args.field.as_str()).expect("could not make bigint");
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let result = modular_exponentiation(b.clone(), e, f);
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let result = modular_exponentiation(b.clone(), e, f, args.verbose);
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if args.machine {
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if args.machine {
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println!("{}", result)
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println!("{}", result)
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}
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}
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@ -1,9 +1,7 @@
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#![allow(dead_code)]
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#![allow(dead_code)]
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use num_bigint::BigInt;
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use num_bigint::{BigInt, BigUint};
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use num_traits::ToPrimitive;
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use num_traits::ToPrimitive;
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use num_traits::FromPrimitive;
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use pyo3::exceptions::PyException;
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use pyo3::exceptions::PyValueError;
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use pyo3::exceptions::PyValueError;
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use pyo3::prelude::*;
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use pyo3::prelude::*;
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@ -16,48 +14,64 @@ pub fn calc_exp_in_field_lib(
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}
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}
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/**
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/**
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* modular exponentiation algorithm with big numbers.
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* square and multiply
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*
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* Umwandlung des Exponenten k in die zugehörige Binärdarstellung.
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* Ersetzen jeder 0 durch Q und jeder 1 durch QM.
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* Nun wird Q als Anweisung zum Quadrieren und M als Anweisung zum Multiplizieren aufgefasst.
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* Somit bildet die resultierende Zeichenkette von links nach rechts gelesen eine Vorschrift zur Berechnung von x k .
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* Man beginne mit 1, quadriere für jedes gelesene Q das bisherige Zwischenergebnis und
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* multipliziere es für jedes gelesene M mit x .
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*/
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*/
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pub fn modular_exponentiation(
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pub fn modular_exponentiation(
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base: BigInt,
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base: BigInt,
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orig_exp: BigInt,
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exp: BigInt,
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field: BigInt) -> BigInt {
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field: BigInt,
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let binary_repr = orig_exp.to_bytes_be();
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verbose: bool) -> BigInt {
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if verbose {
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println!("args:\nbase {base}\nexp {exp}\nfield {field}\nverbose {verbose}");
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}
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let mut instructions: Vec<bool> = bigint_to_bools(exp);
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// remove the signing bit
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if verbose {
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println!("pre instructions {:?}",instructions);
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}
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let instructions: Vec<bool> = bytes_to_bools(&binary_repr.1);
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instructions.reverse();
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if verbose {
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println!("instructions {:?}",instructions);
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}
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let mut exp = BigInt::from(1);
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let mut res = base.clone();
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for instr in instructions {
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for instr in instructions {
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if instr {
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if verbose {
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println!("current res: {res}");
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}
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if !instr {
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// square
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// square
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exp = (exp.pow(2) * &base) % &field;
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if verbose {
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println!("square");
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}
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res = res.pow(2) % &field;
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}
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}
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else {
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else {
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// square and multiply
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// square and multiply
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exp = exp.pow(2) % &field;
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if verbose {
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println!("square and multiply");
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}
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res = (res.pow(2) * &base) % &field;
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}
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}
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}
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}
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return exp;
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return res;
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}
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}
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#[pyfunction]
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#[pyfunction]
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#[pyo3(name="modular_exponentiation")]
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#[pyo3(name="modular_exponentiation")]
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#[pyo3(signature=(base, orig_exp, field, verbose = false))]
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pub fn py_modular_exponentiation(
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pub fn py_modular_exponentiation(
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base: i128,
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base: i128,
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orig_exp: i128,
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orig_exp: i128,
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field: i128) -> PyResult<u128> {
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field: i128,
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verbose: bool) -> PyResult<u128> {
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let big_res = modular_exponentiation(
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let big_res = modular_exponentiation(
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BigInt::from(base),
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BigInt::from(base),
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BigInt::from(orig_exp),
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BigInt::from(orig_exp),
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BigInt::from(field)
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BigInt::from(field),
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verbose
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);
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);
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let res = big_res.to_u128();
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let res = big_res.to_u128();
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match res {
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match res {
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@ -71,17 +85,46 @@ pub fn py_modular_exponentiation(
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}
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}
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// Vec<u8> to Vec<bool> ( binary representation interpreted otherwise )
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/// Dont use this buggy mess
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fn bytes_to_bools(bytes: &Vec<u8>) -> Vec<bool> {
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pub fn binary_exponentiation(base: BigInt, exp: BigInt, verbose: bool) -> BigInt {
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if exp.clone() < BigInt::from(0) {
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return binary_exponentiation(1/&base, -exp, verbose);
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}
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else if exp.clone() == BigInt::from(0) {
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return BigInt::from(1);
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}
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else if exp.clone() % 2 == BigInt::from(0) {
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return binary_exponentiation(&base*&base, &exp/2, verbose);
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}
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else if exp.clone() % 2 == BigInt::from(1) {
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return binary_exponentiation(&base*&base, (&exp-1)/2, verbose);
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}
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else {
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panic!("I don't know how we got here")
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}
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}
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fn bigint_to_bools(item: BigInt) -> Vec<bool> {
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let mut result: Vec<bool> = Vec::new();
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let mut result: Vec<bool> = Vec::new();
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for byte in bytes {
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let mut modul : BigInt;
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for c in format!("{:b}", byte).chars() {
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let mut smaller = item;
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result.push(c == '1');
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loop {
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if smaller < BigInt::from(2) {
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break;
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}
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modul = &smaller % BigInt::from(2);
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smaller = &smaller / BigInt::from(2);
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if modul == BigInt::from(1) {
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result.push(true);
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}
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else {
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result.push(false);
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}
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}
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}
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}
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result
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result
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}
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}
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fn dump_bin(bytes: &Vec<u8>) {
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fn dump_bin(bytes: &Vec<u8>) {
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for byte in bytes.iter() {
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for byte in bytes.iter() {
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println!("{:#08b}\t| {:#02x}", byte, byte);
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println!("{:#08b}\t| {:#02x}", byte, byte);
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