integrals are easy actually????

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Christoph J. Scherr 2024-09-06 15:43:06 +02:00
parent 79d78609f1
commit 595773d2fe
Signed by: cscherrNT
GPG Key ID: 8E2B45BC51A27EA7
2 changed files with 50 additions and 5 deletions

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@ -109,6 +109,7 @@ $
#set enum(numbering: "(a)")
+ $
f(x) &= ln((e^x) / (1+e^x)) \
e(x) = e^x wide a(x) &= (e^x)/(1+e^x) wide b(x) = 1+e^x \
ln: RR^+ |-> RR wide e&: RR |-> RR^+ wide => f: RR |-> RR <=> DD_f = RR \
@ -124,3 +125,47 @@ $
&= (1+e^x)/([1+e^x]^2) \
&= 1/(1+e^x) checkmark
$
+ $
D_f &= RR \\ {x = 1}\
f(x) &= ((x+1)/(x-1))^2 \
a(x) = x+1 wide b(x) = x-1 quad&quad c(x) = a(x)/b(x) wide d(x) = x^2 \
a'(x) = 1 wide b'(x) &= 1 wide d'(x) = 2x \
c'(x) &= (b' dot a - b dot a')/(a^2) \
&= (x-1 - (x+1))/((x-1)^2) \
&= (-2)/((x-1)^2) \
f'(x) &= d'(c(x)) dot c'(x) \
&= 2 dot (x+1)/(x-1) dot (-2)/((x-1)^2) \
&= -4 dot (x+1)/((x-1)^3) checkmark
$
#pagebreak()
=== Exercise 4 @Exercise[1, 4]
#block(
fill: luma(230),
inset: 8pt,
radius: 4pt,
[
Calculate the following integrals using substitution:
#set enum(numbering: "(a)")
+ $ integral (2x+7)/(x^2+7x+3) d x $
+ $ integral (cos(ln(x)))/(x) d x $
])
#set enum(numbering: "(a)")
+ $
A &= integral (2x+7)/(x^2+7x+3) d x \
&= integral (a'(x))/(a(x)) d x \
&= integral (a'(x))/(a(x)) d x \
&= integral 1/(a(x)) dot a'(x) d x; wide d u = a'(x) d x \
&= integral 1/u d u \
&= ln(u) = ln(x^2+7x+3) checkmark
$
+ $
A &= integral (cos(ln(x)))/(x) d x \
&= integral cos(ln(x)) dot 1/x d x \
&= integral cos(u) dot u' d x \
&= integral cos(u) dot d u \
&= sin(u) \
&= sin(ln(x)) \
$