diff --git a/build/main.pdf b/build/main.pdf
index 53c25d2..8ab6d9c 100644
Binary files a/build/main.pdf and b/build/main.pdf differ
diff --git a/src/exercise/1.typ b/src/exercise/1.typ
new file mode 100644
index 0000000..e973a0a
--- /dev/null
+++ b/src/exercise/1.typ
@@ -0,0 +1,53 @@
+== Exercise Sheet 1 - Basics
+
+=== Exercise 1 @Exercise[1, 1]
+
+#block(
+  fill: luma(230),
+  inset: 8pt,
+  radius: 4pt,
+[
+  Determine whether the following sequences converge. Calculate the limit in case of convergence.
+
+  #set enum(numbering: "(a)")
+  + $ a_n = (2024 (1+n+n^2))/(n(n+2023)) $
+  + $ a_n = sqrt(n^2+n dot b_1+b_2)-n; quad b_1,b_2 in RR $
+  + $ a_n = (n^4-2)/(n^2+4) + (n^3(3-n^2))/(n^3+1) $
+])
+
+#set enum(numbering: "(a)")
++ $
+  a_n &= (2024 (1+n+n^2))/(n(n+2023)) \
+  &= ((2024 (1+n+n^2))/n^2)/(1+2023/n) \
+  &= (2024 (1/n^2+1/n+1/))/(1+2023/n) \
+  &= (2024/n^2+2024/n+2024)/(1+2023/n) \
+  
+  => lim_(n -> infinity) a_n &= lim_(n -> infinity) (2024/n^2+2024/n+2024)/(1+2023/n) \
+  &= lim_(n -> infinity) 2024/1 = 2024 checkmark \
+$
+
++ $
+  a_n &= sqrt(n^2+n dot b_1+b_2)-n; quad b_1,b_2 in RR \
+  &= ((sqrt(n^2+n dot b_1+b_2)-n) (sqrt(n^2+n dot b_1+b_2)+n))/(sqrt(n^2+n dot b_1+b_2)+n) \
+  &= (n^2+n dot b_1+b_2 - n^2)/(sqrt(n^2+n dot b_1+b_2)+n) \
+  &= (n dot b_1+b_2)/(sqrt(n^2+n dot b_1+b_2)+n) \
+  &= (b_1+b_2/n)/((sqrt(n^2+n dot b_1+b_2)+n)/n) \
+  &= (b_1+b_2/n)/((sqrt(n^2+n dot b_1+b_2))/n+1) \
+  &= (b_1+b_2/n)/((sqrt(n^2+n dot b_1+b_2))/sqrt(n^2)+1) \
+  &= (b_1+b_2/n)/(sqrt(1+b_1/n+b_2/(n^2))+1) \
+
+  => lim_(n -> infinity) a_n &= lim_(n -> infinity) (b_1+b_2/n)/sqrt(1+b_1/n+b_2/(n^2))+1 \
+  &= b_1/(sqrt(1) + 1) = b_1/2 checkmark
+$
+
++ $ 
+  a_n &= (n^4-2)/(n^2+4) + (n^3(3-n^2)) / (n^3+1) \
+  &= ((n^4-2)(n^3+1) + (n^3(3-n^2))(n^2+4)) / ((n^2+4)(n^3+1)) \
+  &= (n^7+n^4-2n^3-2 + 3n^5+12n^3-n^7-4n^5) / ((n^2+4)(n^3+1)) \
+  &= (-n^5+n^4+10n^3-2) / (n^5+n^2+4n^3+4) \
+  &= (-1+1/n+10/(n^2)-2/(n^5)) / (1+1/(n^3)+4/(n^2)+4/(n^5)) \
+
+  => lim_(n -> infinity) a_n 
+  &= lim_(n -> infinity) (-1+1/n+10/(n^2)-2/(n^5)) / (1+1/(n^3)+4/(n^2)+4/(n^5)) \
+  &= lim_(n -> infinity) -1/1 = 1 checkmark
+$
diff --git a/src/exercise/index.typ b/src/exercise/index.typ
index e69de29..aa9b3b3 100644
--- a/src/exercise/index.typ
+++ b/src/exercise/index.typ
@@ -0,0 +1,2 @@
+
+#include "1.typ"
diff --git a/src/vorlesungen/1.typ b/src/vorlesungen/1.typ
index c896b3b..f8a6250 100644
--- a/src/vorlesungen/1.typ
+++ b/src/vorlesungen/1.typ
@@ -330,7 +330,7 @@ $ <v1-partint>
 
 An dieser Stelle stimmt die Lösung in @Vorlesung leider wieder nicht. Ich habe 
 das Ergebnis wie in <v1-partint> maschinell überprüfen lassen, und es war 
-korrekt. Lauf @Vorlesung wäre das Ergebnis:
+korrekt. Laut @Vorlesung wäre das Ergebnis:
 
 $ A = integral x sin(x) d x = x(-cos(x)) - integral sin(x) d x = cos(x)(1-x) 
 " "#emoji.crossmark $